| Problem 
 | Answer 
 | Comment 
 | 
 | 1 | True |  | 
 | 2 | True |  | 
 | 3 | False |  | 
 | 4 | False | Try substitution. | 
 | 5 | True | Compare with #4. Note that numerator is important. | 
 | 6 | False | This would work, but would require another substitution. What substitution could you use to put this in a known form in one step? | 
 | 7 | True |  | 
 | 8 | False |  | 
 | 10 | False |  | 
 | 11 | False | Did you try a substitution? | 
 | 12 | True |  | 
 | 14 | False | I would try a rationalizing substitution. | 
 | 15 | True |  | 
 | 17 | False | Integrand is not a proper rational function. | 
 | 18 | True |  | 
 | 19 | True |  | 
 | 20 | False | What term is missing? | 
 | 21 | False | This is correct if and only if a=1. | 
 | 22 | False | This is true if the linear polynomials are allowed to have complex coefficients. | 
 | 23 | True |  |