Problem
|
Answer
|
Comment
|
| 1 |
True |
|
| 2 |
True |
|
| 3 |
False |
|
| 4 |
False |
Try substitution. |
| 5 |
True |
Compare with #4. Note that numerator is important. |
| 6 |
False |
This would work, but would require another substitution. What substitution could you use to put this in a known form in one step? |
| 7 |
True |
|
| 8 |
False |
|
| 10 |
False |
|
| 11 |
False |
Did you try a substitution? |
| 12 |
True |
|
| 14 |
False |
I would try a rationalizing substitution. |
| 15 |
True |
|
| 17 |
False |
Integrand is not a proper rational function. |
| 18 |
True |
|
| 19 |
True |
|
| 20 |
False |
What term is missing? |
| 21 |
False |
This is correct if and only if a=1. |
| 22 |
False |
This is true if the linear polynomials are allowed to have complex coefficients. |
| 23 |
True |
|