Problem
|
Answer
|
Comment
|
1 |
True |
|
2 |
True |
|
3 |
False |
|
4 |
False |
Try substitution. |
5 |
True |
Compare with #4. Note that numerator is important. |
6 |
False |
This would work, but would require another substitution. What substitution could you use to put this in a known form in one step? |
7 |
True |
|
8 |
False |
|
10 |
False |
|
11 |
False |
Did you try a substitution? |
12 |
True |
|
14 |
False |
I would try a rationalizing substitution. |
15 |
True |
|
17 |
False |
Integrand is not a proper rational function. |
18 |
True |
|
19 |
True |
|
20 |
False |
What term is missing? |
21 |
False |
This is correct if and only if a=1. |
22 |
False |
This is true if the linear polynomials are allowed to have complex coefficients. |
23 |
True |
|