#! /usr/bin/env python
#
def i4_to_chinese ( j, n, m ):

#*****************************************************************************80
#
## I4_TO_CHINESE converts an integer to its Chinese remainder form.
#
#  Licensing:
#
#    This code is distributed under the GNU LGPL license.
#
#  Modified:
#
#    25 May 2015
#
#  Author:
#
#    John Burkardt
#
#  Parameters:
#
#    Input, integer J, the integer to be converted.
#
#    Input, integer N, the number of moduluses.
#
#    Input, integer M(N), the moduluses.  These should be positive
#    and pairwise prime.
#
#    Output, integer R(N), the Chinese remainder representation of the integer.
#
  import numpy as np
  from sys import exit
  from chinese_check import chinese_check
  from i4_modp import i4_modp

  ierror = chinese_check ( n, m )

  if ( ierror != 0 ):
    print ( '' )
    print ( 'I4_TO_CHINESE - Fatal error!' )
    print ( '  The moduluses are not legal.' )
    exit ( 'I4_TO_CHINESE - Fatal error!' )

  r = np.zeros ( n )

  for i in range ( 0, n ):
    r[i] = i4_modp ( j, m[i] )

  return r

def i4_to_chinese_test ( ):

#*****************************************************************************80
#
## I4_TO_CHINESE_TEST tests I4_TO_CHINESE.
#
#  Licensing:
#
#    This code is distributed under the GNU LGPL license.
#
#  Modified:
#
#    25 May 2015
#
#  Author:
#
#    John Burkardt
#
  import numpy as np
  import platform
  from chinese_to_i4 import chinese_to_i4
  from i4vec_print import i4vec_print

  n = 4
  m = np.array ( [ 3, 4, 5, 7 ] )

  print ( '' )
  print ( 'I4_TO_CHINESE_TEST' )
  print ( '  Python version: %s' % ( platform.python_version ( ) ) )
  print ( '  I4_TO_CHINESE computes the Chinese Remainder' )
  print ( '  representation of an integer.' )

  i4vec_print ( n, m, '  The moduli:' )

  j = 37

  print ( '' )
  print ( '  The number being analyzed is %d' % ( j ) )

  r = i4_to_chinese ( j, n, m )

  i4vec_print ( n, r, '  The remainders:' )

  j2 = chinese_to_i4 ( n, m, r )

  print ( '' )
  print ( '  The reconstructed number is %d' % ( j2 ) )

  r = i4_to_chinese ( j2, n, m )

  i4vec_print ( n, r, '  The remainders of the reconstructed number are:' )
#
#  Terminate.
#
  print ( '' )
  print ( 'I4_TO_CHINESE_TEST:' )
  print ( '  Normal end of execution.' )
  return

if ( __name__ == '__main__' ):
  from timestamp import timestamp
  timestamp ( )
  i4_to_chinese_test ( )
  timestamp ( )