#! /usr/bin/env python # def polyomino_enumerate_fixed ( n_data ): #*****************************************************************************80 # ## POLYOMINO_ENUMERATE_FIXED counts fixed polyominoes (allowing holes). # # Discussion: # # Polyominoes are connected planar shapes formed by adjoining unit squares. # # The number of unit squares in a polyomino is its order. # # If we do not ignore reflections and rotations when comparing polyominoes, # then we are considering the class of "fixed" polyominoes. In that case, # for instance, there are 65 fixed polyominoes of order 5. # # As the order increases, the number of polyominoes grows very rapidly. # The list offered here goes no further than order 28, but the later # numbers in the list are too large to represent as 32 byte integers. # # Licensing: # # This code is distributed under the GNU LGPL license. # # Modified: # # 10 April 2018 # # Author: # # John Burkardt # # Reference: # # Solomon Golomb, # Polyominoes: Puzzles, Patterns, Problems, and Packings, # Princeton University Press, 1996, # ISBN: 9780691024448 # # Parameters: # # Input/output, integer N_DATA. The user sets N_DATA to 0 before the # first call. On each call, the routine increments N_DATA by 1, and # returns the corresponding data; when there is no more data, the # output value of N_DATA will be 0 again. # # Output, integer ORDER, the order of a polyomino. # # Output, integer NUMBER, the number of fixed polyominos of this order. # import numpy as np n_max = 29 order_vec = np.array ( [ \ 0, \ 1, 2, 3, 4, 5, \ 6, 7, 8, 9, 10, \ 11, 12, 13, 14, 15, \ 16, 17, 18, 19, 20, \ 21, 22, 23, 24, 25, \ 26, 27, 28 ] ) number_vec = np.array ( [ \ 1, \ 1, 2, 6, 19, 63, \ 216, 760, 2725, 9910, 36446, \ 135268, 505861, 1903890, 7204874, 27394666, \ 104592937, 400795844, 1540820542, 5940738676, 22964779660, \ 88983512783, 345532572678, 1344372335524, 5239988770268, 20457802016011, \ 79992676367108, 313224032098244, 1228088671826973 ] ) if ( n_data < 0 ): n_data = 0 if ( n_max <= n_data ): n_data = 0 order = 0 number = 0 else: order = order_vec[n_data] number = number_vec[n_data] n_data = n_data + 1 return n_data, order, number def polyomino_enumerate_fixed_test ( ): #*****************************************************************************80 # ## POLYOMINO_ENUMERATE_FIXED_TEST tests POLYOMINO_ENUMERATE_FIXED. # # Licensing: # # This code is distributed under the GNU LGPL license. # # Modified: # # 10 April 2018 # # Author: # # John Burkardt # print ( '' ) print ( 'POLYOMINO_ENUMERATEv_FIXED_TEST:' ) print ( ' POLYOMINO_ENUMERATE_FIXED returns counts of' ) print ( ' the number of fixed polyominoes.' ) print ( '' ) print ( ' Order Number' ) print ( '' ) n_data = 0 while ( True ): n_data, order, number = polyomino_enumerate_fixed ( n_data ) if ( n_data == 0 ): break print ( ' %d %d' % ( order, number ) ) # # Terminate. # print ( '' ) print ( 'POLYOMINO_ENUMERATE_FIXED_TEST:' ) print ( ' Normal end of execution.' ) return if ( __name__ == '__main__' ): from timestamp import timestamp timestamp ( ) polyomino_enumerate_fixed_test ( ) timestamp ( )