# include # include # include # include # include using namespace std; # include "subset_sum_serial.hpp" //****************************************************************************80 int i4_power ( int i, int j ) //****************************************************************************80 // // Purpose: // // I4_POWER returns the value of I^J. // // Licensing: // // This code is distributed under the GNU LGPL license. // // Modified: // // 01 April 2004 // // Author: // // John Burkardt // // Parameters: // // Input, int I, J, the base and the power. J should be nonnegative. // // Output, int I4_POWER, the value of I^J. // { int k; int value; if ( j < 0 ) { if ( i == 1 ) { value = 1; } else if ( i == 0 ) { cerr << "\n"; cerr << "I4_POWER - Fatal error!\n"; cerr << " I^J requested, with I = 0 and J negative.\n"; exit ( 1 ); } else { value = 0; } } else if ( j == 0 ) { if ( i == 0 ) { cerr << "\n"; cerr << "I4_POWER - Fatal error!\n"; cerr << " I^J requested, with I = 0 and J = 0.\n"; exit ( 1 ); } else { value = 1; } } else if ( j == 1 ) { value = i; } else { value = 1; for ( k = 1; k <= j; k++ ) { value = value * i; } } return value; } /******************************************************************************/ int *i4_to_digits_binary ( int i, int n ) /******************************************************************************/ /* Purpose: I4_TO_DIGITS_BINARY produces the binary digits of an I4. Example: I N C Binary -- --- --- ------------ 0 1 0 0 0 2 0, 0 00 1 3 1, 0, 0 100 2 3 0, 1, 0 010 3 3 1, 1, 0 011 4 3 0, 0, 1 100 8 3 0, 0, 0 (1)000 8 5 0, 0, 0, 1, 0 01000 -8 5 0, 0, 0, 1, 0 (-) 01000 0 3 0, 0, 0 1 3 1, 0, 0 2 3 0, 1, 0 3 3 1, 1, 0 4 3 0, 0, 1 5 3 1, 0, 1 6 3 0, 1, 1 7 3 1, 1, 1 Licensing: This code is distributed under the GNU LGPL license. Modified: 19 December 2011 Author: John Burkardt Parameters: Input, int I, the integer to be analyzed. Input, int N, the number of digits to determine. Output, int I4_TO_DIGITS_BINARY[N], the first N binary digits of I. Entry 0 is the units digit. */ { int *c; int j; c = ( int * ) malloc ( n * sizeof ( int ) ); i = abs ( i ); for ( j = 0; j < n; j++ ) { c[j] = i % 2; i = ( i - c[j] ) / 2; } return c; } //****************************************************************************80 int i4vec_dot_product ( int n, int x[], int y[] ) //****************************************************************************80 // // Purpose: // // I4VEC_DOT_PRODUCT computes the dot product of two I4VEC's. // // Discussion: // // An I4VEC is a vector of I4's. // // Licensing: // // This code is distributed under the GNU LGPL license. // // Modified: // // 19 December 2011 // // Author: // // John Burkardt // // Parameters: // // Input, int N, the size of the array. // // Input, int X[N], Y[N], the arrays. // // Output, int I4VEC_DOT_PRODUCT, the dot product of X and Y. // { int i; int value; value = 0; for ( i = 0; i < n; i++ ) { value = value + x[i] * y[i]; } return value; } //****************************************************************************80 int *subset_sum_serial ( int n, int weight[], int target ) //****************************************************************************80 // // Purpose: // // SUBSET_SUM_SERIAL seeks a subset of a set that has a given sum. // // Discussion: // // This function tries to compute a target value as the sum of // a selected subset of a given set of weights. // // This function works by brute force, that is, it tries every // possible subset to see if it sums to the desired value. // // Given N weights, every possible selection can be described by // one of the N-digit binary numbers from 0 to 2^N-1. // // It is possible that there may be multiple solutions of the problem. // This function will only return the first solution found. // // Example: // // n = 6 // target = 22 // w = (/ 1, 2, 4, 8, 16, 32 /) // // choice = (/ 0, 1, 1, 0, 1, 0 /) // w(choice) = 2 + 4 + 16 = 22 // // Licensing: // // This code is distributed under the GNU LGPL license. // // Modified: // // 01 July 2013 // // Author: // // John Burkardt // // Parameters: // // Input, int N, the number of weights. // // Input, int WEIGHT[N], the weights. // // Input, int TARGET, the target value. // // Output, int SUBSET_SUM_SERIAL[N], contains a 1 for each // weight that is chosen. If no solution was found, all entries // are returned as -1. // { int *choice; int i; int i_max; int w_sum; i_max = i4_power ( 2, n ); for ( i = 0; i < i_max; i++ ) { // // Convert I to a string of binary digits. // choice = i4_to_digits_binary ( i, n ); // // Combine the weights whose binary digit is 1. // w_sum = i4vec_dot_product ( n, choice, weight ); // // Return if we matched our target sum. // if ( w_sum == target ) { return choice; } delete [] choice; } choice = new int[n]; for ( i = 0; i < n; i++ ) { choice[i] = -1; } return choice; } //****************************************************************************80 void timestamp ( ) //****************************************************************************80 // // Purpose: // // TIMESTAMP prints the current YMDHMS date as a time stamp. // // Example: // // 31 May 2001 09:45:54 AM // // Licensing: // // This code is distributed under the GNU LGPL license. // // Modified: // // 08 July 2009 // // Author: // // John Burkardt // // Parameters: // // None // { # define TIME_SIZE 40 static char time_buffer[TIME_SIZE]; const struct std::tm *tm_ptr; std::time_t now; now = std::time ( NULL ); tm_ptr = std::localtime ( &now ); std::strftime ( time_buffer, TIME_SIZE, "%d %B %Y %I:%M:%S %p", tm_ptr ); std::cout << time_buffer << "\n"; return; # undef TIME_SIZE }