# include # include # include # include "point_merge.h" int main ( ); void test01 ( int m, int n, int n_unique, int seed ); void test02 ( int m, int n, int n_unique, double tol, int seed ); void test03 ( int m, int n, int n_unique, double tol, int seed ); void test04 ( int m, int n, int n_unique, double tol, int seed ); void test05 ( int m, int n, int n_unique, double tol, int seed ); /******************************************************************************/ int main ( ) /******************************************************************************/ /* Purpose: MAIN is the main program for POINT_MERGE_TEST. Discussion: POINT_MERGE_TEST tests the POINT_MERGE library. Compare correctness of the codes. Compare speed of the codes. Licensing: This code is distributed under the GNU LGPL license. Modified: 25 July 2010 Author: John Burkardt */ { int m; int n; int n_unique; int seed; double tol; timestamp ( ); printf ( " \n" ); printf ( "POINT_MERGE_TEST\n" ); printf ( " C version\n" ); printf ( " Test the POINT_MERGE library.\n" ); /* TEST01 gives me some confidence that, at least for zero-tolerance, the radial approach is accurate, as compared to the "Unique count" (which cannot be extended to a tolerance version in multidimensions) and the "Tol Unique Count", which is an O(N^2) algorithm. */ m = 3; n = 10; n_unique = 7; seed = 123456789; test01 ( m, n, n_unique, seed ); m = 4; n = 20; n_unique = 11; seed = 987654321; test01 ( m, n, n_unique, seed ); /* In TEST02, I want to compute the same data, but with "blurred" duplicates, and a tolerance version of the radial approach, compared to "Tol Unique Count". */ m = 3; n = 10; n_unique = 7; tol = 0.00001; seed = 123456789; test02 ( m, n, n_unique, tol, seed ); m = 4; n = 20; n_unique = 11; tol = 0.00001; seed = 987654321; test02 ( m, n, n_unique, tol, seed ); /* In TEST03, I want to measure the time required for a sequence of increasingly hard problems. */ m = 3; n = 100; n_unique = n / 2; tol = 0.00001; seed = 123456789; test03 ( m, n, n_unique, tol, seed ); m = 3; n = 1000; n_unique = n / 2; tol = 0.00001; seed = 123456789; test03 ( m, n, n_unique, tol, seed ); m = 3; n = 10000; n_unique = n / 2; tol = 0.00001; seed = 123456789; test03 ( m, n, n_unique, tol, seed ); if ( 0 ) { m = 3; n = 100000; n_unique = n / 2; tol = 0.00001; seed = 123456789; test03 ( m, n, n_unique, tol, seed ); } /* In TEST04, repeat TEST02, but now compute the index vector. */ m = 3; n = 10; n_unique = 7; tol = 0.00001; seed = 123456789; test04 ( m, n, n_unique, tol, seed ); m = 4; n = 20; n_unique = 11; tol = 0.00001; seed = 987654321; test04 ( m, n, n_unique, tol, seed ); /* In TEST05, I want to measure the time required for a sequence of increasingly hard problems. */ m = 3; n = 100; n_unique = n / 2; tol = 0.00001; seed = 123456789; test05 ( m, n, n_unique, tol, seed ); m = 3; n = 1000; n_unique = n / 2; tol = 0.00001; seed = 123456789; test05 ( m, n, n_unique, tol, seed ); m = 3; n = 10000; n_unique = n / 2; tol = 0.00001; seed = 123456789; test05 ( m, n, n_unique, tol, seed ); if ( 0 ) { m = 3; n = 100000; n_unique = n / 2; tol = 0.00001; seed = 123456789; test05 ( m, n, n_unique, tol, seed ); } /* Terminate. */ printf ( " \n" ); printf ( "POINT_MERGE_TEST\n" ); printf ( " Normal end of execution.\n" ); printf ( " \n" ); timestamp ( ); return 0; } /******************************************************************************/ void test01 ( int m, int n, int n_unique, int seed ) /******************************************************************************/ /* Purpose: TEST01 tests uniqueness counting with no tolerance. Discussion: POINT_UNIQUE_COUNT uses an O(N) algorithm. POINT_RADIAL_UNIQUE_COUNT uses an algorithm that should be, in general, O(N); POINT_TOL_UNIQUE_COUNT uses an O(N^2) algorithm. For this test, we just want to make sure the algorithms agree in the counting. Licensing: This code is distributed under the GNU LGPL license. Modified: 25 July 2010 Author: John Burkardt */ { double *a; double tol; int unique_num; printf ( " \n" ); printf ( "TEST01\n" ); printf ( " To count the unique columns in an R8COL, we call\n" ); printf ( " POINT_UNIQUE_COUNT,\n" ); printf ( " POINT_RADIAL_UNIQUE_COUNT, (with random center)\n" ); printf ( " POINT_TOL_UNIQUE_COUNT, (with zero tolerance)\n" ); printf ( " \n" ); printf ( " M = %d\n", m ); printf ( " N = %d\n", n ); printf ( " SEED = %d\n",seed ); a = r8col_duplicates ( m, n, n_unique, &seed ); r8mat_transpose_print ( m, n, a, " Matrix with N_UNIQUE unique columns:" ); printf ( " \n" ); printf ( " N_UNIQUE = %d\n", n_unique ); unique_num = point_unique_count ( m, n, a ); printf ( " POINT_UNIQUE_COUNT = %d\n", unique_num ); unique_num = point_radial_unique_count ( m, n, a, &seed ); printf ( " POINT_RADIAL_UNIQUE_COUNT = %d\n", unique_num ); tol = 0.0; unique_num = point_tol_unique_count ( m, n, a, tol ); printf ( " POINT_TOL_UNIQUE_COUNT = %d\n", unique_num ); free ( a ); return; } /******************************************************************************/ void test02 ( int m, int n, int n_unique, double tol, int seed ) /******************************************************************************/ /* Purpose: TEST02 tests uniqueness counting with a tolerance. Discussion: POINT_RADIAL_TOL_UNIQUE_COUNT uses an algorithm that should be, in general, O(N); POINT_TOL_UNIQUE_COUNT uses an O(N^2) algorithm. For this test, we just want to make sure the algorithms agree in the counting. Licensing: This code is distributed under the GNU LGPL license. Modified: 25 July 2010 Author: John Burkardt */ { double *a; int i; int j; double *r; double r_norm; int unique_num; printf ( " \n" ); printf ( "TEST02\n" ); printf ( " To count the unique columns in an R8COL, we call\n" ); printf ( " POINT_RADIAL_TOL_UNIQUE_COUNT, (with random center)\n" ); printf ( " POINT_TOL_UNIQUE_COUNT, (with zero tolerance)\n" ); printf ( " \n" ); printf ( " M = %d\n", m ); printf ( " N = %d\n", n ); printf ( " TOL = %e\n", tol ); printf ( " SEED = %d\n", seed ); a = r8col_duplicates ( m, n, n_unique, &seed ); r8mat_transpose_print ( m, n, a, " Matrix with N_UNIQUE unique columns:" ); /* The form of the tolerance test means that if two vectors are initially equal, they remain "tolerably equal" after the addition of random perturbation vectors whose 2-norm is no greater than TOL/2. */ r = ( double * ) malloc ( m * sizeof ( double ) ); for ( j = 0; j < n; j++ ) { r8vec_uniform_01 ( m, &seed, r ); r_norm = r8vec_norm_l2 ( m, r ); for ( i = 0; i < m; i++ ) { a[i+j*m] = a[i+j*m] + 0.5 * tol * r[i] / r_norm; } } free ( r ); r8mat_transpose_print ( m, n, a, " Blurred matrix:" ); printf ( " \n" ); printf ( " N_UNIQUE = %d\n", n_unique ); unique_num = point_radial_tol_unique_count ( m, n, a, tol, &seed ); printf ( " POINT_RADIAL_TOL_UNIQUE_COUNT = %d\n", unique_num ); unique_num = point_tol_unique_count ( m, n, a, tol ); printf ( " POINT_TOL_UNIQUE_COUNT = %d\n", unique_num ); free ( a ); return; } /******************************************************************************/ void test03 ( int m, int n, int n_unique, double tol, int seed ) /******************************************************************************/ /* Purpose: TEST03 compares timings for two uniqueness counters. Discussion: POINT_RADIAL_TOL_UNIQUE_COUNT uses an algorithm that should be, in general, O(N); POINT_TOL_UNIQUE_COUNT uses an O(N^2) algorithm. Licensing: This code is distributed under the GNU LGPL license. Modified: 25 July 2010 Author: John Burkardt */ { double *a; double ctime; int i; int j; double *r; double r_norm; int unique_num; printf ( " \n" ); printf ( "TEST03\n" ); printf ( " To count the unique columns in an R8COL, we call\n" ); printf ( " POINT_RADIAL_TOL_UNIQUE_COUNT, (with random center)\n" ); printf ( " POINT_TOL_UNIQUE_COUNT, (with zero tolerance)\n" ); printf ( " \n" ); printf ( " M = %d\n", m ); printf ( " N = %d\n", n ); printf ( " TOL = %e\n", tol ); printf ( " SEED = %d\n", seed ); a = r8col_duplicates ( m, n, n_unique, &seed ); /* The form of the tolerance test means that if two vectors are initially equal, they remain "tolerably equal" after the addition of random perturbation vectors whose 2-norm is no greater than TOL/2. */ r = ( double * ) malloc ( m * sizeof ( double ) ); for ( j = 0; j < n; j++ ) { r8vec_uniform_01 ( m, &seed, r ); r_norm = r8vec_norm_l2 ( m, r ); for ( i = 0; i < m; i++ ) { a[i+j*m] = a[i+j*m] + 0.5 * tol * r[i] / r_norm; } } free ( r ); printf ( " \n" ); printf ( " N_UNIQUE = %d\n", n_unique ); ctime = cpu_time ( ); unique_num = point_radial_tol_unique_count ( m, n, a, tol, &seed ); ctime = cpu_time ( ) - ctime; printf ( " \n" ); printf ( " POINT_RADIAL_TOL_UNIQUE_COUNT = %d\n", unique_num ); printf ( " CPU_TIME = %f\n", ctime ); ctime = cpu_time ( ); unique_num = point_tol_unique_count ( m, n, a, tol ); ctime = cpu_time ( ) - ctime; printf ( " \n" ); printf ( " POINT_TOL_UNIQUE_COUNT = %d\n", unique_num ); printf ( " CPU_TIME = %f\n", ctime ); free ( a ); return; } /******************************************************************************/ void test04 ( int m, int n, int n_unique, double tol, int seed ) /******************************************************************************/ /* Purpose: TEST04 tests uniqueness indexing with a tolerance. Discussion: POINT_RADIAL_TOL_UNIQUE_COUNT uses an algorithm that should be, in general, O(N); POINT_TOL_UNIQUE_COUNT uses an O(N^2) algorithm. For this test, we just want to make sure the algorithms agree in the counting. Licensing: This code is distributed under the GNU LGPL license. Modified: 28 July 2010 Author: John Burkardt */ { double *a; double dist; int i; int j; int k; double *r; double r_norm; int *undx; int unique_num; int *xdnu; printf ( " \n" ); printf ( "TEST04\n" ); printf ( " To index the unique columns in an R8COL, we call\n" ); printf ( " POINT_RADIAL_TOL_UNIQUE_COUNT, (with random center)\n" ); printf ( " POINT_TOL_UNIQUE_COUNT, (with zero tolerance)\n" ); printf ( " \n" ); printf ( " M = %d\n", m ); printf ( " N = %d\n", n ); printf ( " TOL = %e\n", tol ); printf ( " SEED = %d\n", seed ); a = r8col_duplicates ( m, n, n_unique, &seed ); r8mat_transpose_print ( m, n, a, " Matrix with N_UNIQUE unique columns:" ); /* The form of the tolerance test means that if two vectors are initially equal, they remain "tolerably equal" after the addition of random perturbation vectors whose 2-norm is no greater than TOL/2. */ r = ( double * ) malloc ( m * sizeof ( double ) ); for ( j = 0; j < n; j++ ) { r8vec_uniform_01 ( m, &seed, r ); r_norm = r8vec_norm_l2 ( m, r ); for ( i = 0; i < m; i++ ) { a[i+j*m] = a[i+j*m] + 0.5 * tol * r[i] / r_norm; } } free ( r ); r8mat_transpose_print ( m, n, a, " Blurred matrix:" ); printf ( " \n" ); printf ( " N_UNIQUE = %d\n", n_unique ); undx = ( int * ) malloc ( n * sizeof ( int ) ); xdnu = ( int * ) malloc ( n * sizeof ( int ) ); unique_num = point_radial_tol_unique_index ( m, n, a, tol, &seed, undx, xdnu ); printf ( " \n" ); printf ( " POINT_RADIAL_TOL_UNIQUE_INDEX\n" ); printf ( " Unique_num = %d\n", unique_num ); i4vec_print ( unique_num, undx, " UNDX:" ); i4vec_print ( n, xdnu, " XDNU:" ); printf ( " \n" ); printf ( " List of nonunique points P(J), represented by\n" ); printf ( " point with index I(J).\n" ); printf ( " \n" ); printf ( " J, P(J)\n" ); printf ( " I(J), P(I(J))\n" ); printf ( " || P(J) - P(I(J)) || (should be <= TOL)\n" ); printf ( " \n" ); for ( j = 0; j < n; j++ ) { k = undx[xdnu[j]]; if ( j != k ) { printf ( " \n" ); printf ( " %4d", j ); for ( i = 0; i < m; i++ ) { printf ( " %10f", a[i+j*m] ); } printf ( "\n" ); printf ( " %4d", k ); for ( i = 0; i < m; i++ ) { printf ( " %10f", a[i+k*m] ); } printf ( "\n" ); dist = 0.0; for ( i = 0; i < m; i++ ) { dist = dist + pow ( a[i+j*m] - a[i+k*m], 2 ); } dist = sqrt ( dist ); printf ( " %10e\n", dist ); } } /* The interpretation of XDNU is simpler for POINT_TOL_UNIQUE_INDEX. */ unique_num = point_tol_unique_index ( m, n, a, tol, xdnu ); printf ( " \n" ); printf ( " POINT_TOL_UNIQUE_INDEX\n" ); printf ( " Unique_num = %d\n", unique_num ); printf ( " \n" ); printf ( " List of nonunique points P(J), represented by\n" ); printf ( " point with index I(J).\n" ); printf ( " \n" ); printf ( " J, P(J)\n" ); printf ( " I(J), P(I(J))\n" ); printf ( " || P(J) - P(I(J)) || (should be <= TOL)\n" ); printf ( " \n" ); for ( j = 0; j < n; j++ ) { k = xdnu[j]; if ( j != k ) { printf ( " \n" ); printf ( " %4d", j ); for ( i = 0; i < m; i++ ) { printf ( " %10f", a[i+j*m] ); } printf ( "\n" ); printf ( " %4d", k ); for ( i = 0; i < m; i++ ) { printf ( " %10f", a[i+k*m] ); } printf ( "\n" ); dist = 0.0; for ( i = 0; i < m; i++ ) { dist = dist + pow ( a[i+j*m] - a[i+k*m], 2 ); } dist = sqrt ( dist ); printf ( " %10e\n", dist ); } } free ( a ); free ( undx ); free ( xdnu ); return; } /******************************************************************************/ void test05 ( int m, int n, int n_unique, double tol, int seed ) /******************************************************************************/ /* Purpose: TEST05 times uniqueness indexing with a tolerance. Discussion: POINT_RADIAL_TOL_UNIQUE_COUNT uses an algorithm that should be, in general, O(N); POINT_TOL_UNIQUE_COUNT uses an O(N^2) algorithm. For this test, we just want to make sure the algorithms agree in the counting. Licensing: This code is distributed under the GNU LGPL license. Modified: 28 July 2010 Author: John Burkardt */ { double *a; double ctime; double dist; int i; int j; double *r; double r_norm; int *undx; int unique_num; int *xdnu; printf ( " \n" ); printf ( "TEST05\n" ); printf ( " We time the computations in TEST04, calling\n" ); printf ( " POINT_RADIAL_TOL_UNIQUE_COUNT, (with random center)\n" ); printf ( " POINT_TOL_UNIQUE_COUNT, (with zero tolerance)\n" ); printf ( " \n" ); printf ( " M = %d\n", m ); printf ( " N = %d\n", n ); printf ( " TOL = %e\n", tol ); printf ( " SEED = %d\n", seed ); a = r8col_duplicates ( m, n, n_unique, &seed ); /* The form of the tolerance test means that if two vectors are initially equal, they remain "tolerably equal" after the addition of random perturbation vectors whose 2-norm is no greater than TOL/2. */ r = ( double * ) malloc ( m * sizeof ( double ) ); for ( j = 0; j < n; j++ ) { r8vec_uniform_01 ( m, &seed, r ); r_norm = r8vec_norm_l2 ( m, r ); for ( i = 0; i < m; i++ ) { a[i+j*m] = a[i+j*m] + 0.5 * tol * r[i] / r_norm; } } free ( r ); printf ( " \n" ); printf ( " N_UNIQUE = %d\n", n_unique ); undx = ( int * ) malloc ( n * sizeof ( int ) ); xdnu = ( int * ) malloc ( n * sizeof ( int ) ); ctime = cpu_time ( ); unique_num = point_radial_tol_unique_index ( m, n, a, tol, &seed, undx, xdnu ); ctime = cpu_time ( ) - ctime; printf ( " \n" ); printf ( " POINT_RADIAL_TOL_UNIQUE_INDEX\n" ); printf ( " Unique_num = %d\n", unique_num ); printf ( " Time = %f\n", ctime ); ctime = cpu_time ( ); unique_num = point_tol_unique_index ( m, n, a, tol, xdnu ); ctime = cpu_time ( ) - ctime; printf ( " \n" ); printf ( " POINT_TOL_UNIQUE_INDEX\n" ); printf ( " Unique_num = %d\n", unique_num ); printf ( " Time = %f\n", ctime ); free ( a ); free ( undx ); free ( xdnu ); return; }